[最も共有された！ √] 2^n 2^n-1/2^n 1-2^n 172297-3(2^n+1)-4(2^n-1)/2^n+1-2^n
Let L = ∏ n = 3 ∞ ( 1 − n 2 4 );
3(2^n+1)-4(2^n-1)/2^n+1-2^n-Solution for n^21= equation Simplifying n 2 1 = 0 Reorder the terms 1 n 2 = 0 Solving 1 n 2 = 0 Solving for variable 'n' Move all terms containing n to the left, all other terms to the right Add '1' to each side of the equation 1 1 n 2 = 0 1 Combine like terms 1 1 = 0 0 n 2 = 0 1 n 2 = 0 1 Combine like terms 0 1 = 1 n 2 = 1 Simplifying n 2 = 1 Take the squareLittle ant said 1^2 2^2 3^2 2^n = 2^ (n1) This makes absolutely no sense I mean, look at it for a second firstly you failed to notice the pattern correctly since 2^n means 2^12^22^3 instead of what is shown And secondly, how can that all equal 2^ (n1) when on the left side of the equation, you already have 2^n which means
3(2^n+1)-4(2^n-1)/2^n+1-2^nのギャラリー
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